Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises: 19

Answer

$10,18,42,114$

Work Step by Step

$a_{n+1} = 3a_n-12$ $a_1 = 10$ To find the first four terms, we need to find $a_1, a_2, a_3$, and $a_4$. $a_1 = 10$ $a_2 = 3(10)-12 = 18$ $a_3 = 3(18)-12 = 42$ $a_4 = 3(42)-12 = 114$
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