## Calculus: Early Transcendentals (2nd Edition)

$$\sum_{k=1}^{n} k^2$$ Sum of first four terms would be when n = 4. $$\sum_{k=1}^{4} k^2= 1^2 + 2 ^2 + 3^3 + 4^4 = 1 + 4 + 9 + 16 = 30$$