Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.1 An Overview - 8.1 Exercises: 21

Answer

$0,2,15,679$

Work Step by Step

$a_{n+1} = 3_n^2 + n + 1$ $a_1 = 0$ To find the first four terms, we need to find $a_1, a_2, a_3$, and $a_4$. $a_1 = 0$ $a_2 = 3(0)^2 + 1 + 1 = 2$ $a_3 = 3(2)^2 + 2 + 1 = 15$ $a_4 = 3(15)^2 + 3 + 1 = 679$
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