Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.9 Derivatives of Logarithmic and Exponential Functions - 3.9 Exercises: 44

Answer

$f'(x) = \pi(2^x+1)^{\pi-1} 2^x\ln(2) $

Work Step by Step

If $f(x) = b^x$, then $f'(x) = b^x\ln(b)$ $f(x) = (2^x+1)^\pi$ Using General Power Rule and Chain Rule: $f'(x) = \pi(2^x+1)^{\pi-1} 2^x\ln(2) $
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