Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.9 Derivatives of Logarithmic and Exponential Functions - 3.9 Exercises - Page 211: 35

Answer

$f'(x) = 2^x\ln(2)$

Work Step by Step

If $f(x) = b^x$, then $f'(x) = b^x\ln(b)$ $f(x) = 2^x$ $f'(x) = 2^x\ln(2)$
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