Answer
$\dfrac {9}{4}=2.25$
Work Step by Step
$\lim _{t\rightarrow 2}\dfrac {t^{2}+5}{1+\sqrt {t^{2}+5}}=\dfrac {2^{2}+5}{1+\sqrt {2^{2}+5}}=\dfrac {9}{1+\sqrt {9}}=\dfrac {9}{4}=2.25$
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