Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises: 33

Answer

$=\ln 2\approx 0.693$

Work Step by Step

$\lim _{x\rightarrow 0}\ln \dfrac {2\sin x}{x}=\ln \dfrac {2x}{x}=\ln 2\approx 0.693$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.