Answer
$3$
Work Step by Step
$\lim _{x\rightarrow 2}\sqrt {\dfrac {4x+10}{2x-2}}=\sqrt {\dfrac {4\times 2+10}{2\times 2-2}}=\sqrt {\dfrac {18}{2}}=\sqrt {9}=3$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.6 Continuity - 2.6 Exercises - Page 109: 47
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