Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 42

Answer

$-5$

Work Step by Step

$\lim _{t\rightarrow 2}\dfrac {3t^{2}-7t+2}{2-t}=\dfrac {3t^{2}-6t-t+2}{2-t}=\dfrac {3t\left( t-2\right) -\left( t-2\right) }{2-t}=\dfrac {\left( t-2\right) \left( 3t-1\right) }{-\left( t-2\right) }=-\left( 3t-1\right) =-\left( 3\times 2-1\right) =-5$
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