Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 77: 31

Answer

$-5$

Work Step by Step

$\lim _{x\rightarrow 3}\dfrac {-5x}{\sqrt {4x-3}}=\dfrac {-5\times 3}{\sqrt {4\times 3-3}}=\dfrac {-15}{\sqrt {12-3}}=-\dfrac {15}{\sqrt {9}}=-\dfrac {15}{3}=-5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.