Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 41

Answer

-8

Work Step by Step

$\lim\limits_{x \to 4}$ $\frac{x^{2}-16}{4-x}$ = $\lim\limits_{x \to 4}$ $\frac{(x-4)(x+4)}{-(x+4)}$ = $\lim\limits_{x \to 4}$ $\frac{(x+4)}{-1}$ = $\lim\limits_{x \to 4}$ -(x+4) = - (4+4) =-8
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