Answer
-8
Work Step by Step
$\lim\limits_{x \to 4}$ $\frac{x^{2}-16}{4-x}$
= $\lim\limits_{x \to 4}$ $\frac{(x-4)(x+4)}{-(x+4)}$
= $\lim\limits_{x \to 4}$ $\frac{(x+4)}{-1}$
= $\lim\limits_{x \to 4}$ -(x+4)
= - (4+4)
=-8
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 77: 41
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