Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises: 21

Answer

$\left( y-\dfrac {1}{y}\right) \left( y+\dfrac {1}{y}\right) $

Work Step by Step

$y^{2}-y^{-2}=y^{2}-\dfrac {1}{y^{2}}=\left( y-\dfrac {1}{y}\right) \left( y+\dfrac {1}{y}\right) $
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