Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises: 19

Answer

$\dfrac {-h}{x\left( x+h\right) }$

Work Step by Step

$\dfrac {1}{x+n}-\dfrac {1}{x}=\dfrac {x-\left( x+h\right) }{\left( x+h\right) x}=\dfrac {-h}{x\left( x+h\right) }$
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