Answer
$4$
Work Step by Step
$\left( \dfrac {1}{8}\right) ^{-2/3}=\left( \left( \dfrac {1}{8}\right) ^{\dfrac {1}{3}}\right) ^{-2}=\left( \sqrt [3] {\dfrac {1}{8}}\right) ^{-2}=\left( \dfrac {1}{2}\right) ^{-2}=2^{2}=4$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Appendix A - Appendix A Exercises - Page 1158: 15
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