Answer
$\frac{1-3t^2}{1+t-t^3}$
Work Step by Step
$\frac{d}{dt}\ln|1+t-t^3|$
$=\frac{1}{1+t-t^3}*\frac{d}{dx}(1+t-t^3)$
$=\frac{1}{1+t-t^3}*(1-3t^2)$
$=\frac{1-3t^2}{1+t-t^3}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.4 Derivatives of Logarithmic Functions - 6.4 Exercises - Page 436: 16
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