Answer
$\frac{-\sin x}{(1+\cos x)\ln 10}$
Work Step by Step
$\frac{d}{dx}\log_{10}(1+\cos x)$
$=\frac{1}{(1+\cos x)\ln 10}\frac{d}{dx}(1+\cos x)$
$=\frac{-\sin x}{(1+\cos x)\ln 10}$
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