Answer
(a) $dy$ = $\frac{1+sint}{2\sqrt {t-cost}}dt$
(b) $dy$ = $[\frac{1}{x}cosx-\frac{1}{x^{2}}sinx]dx$
Work Step by Step
(a)
$\frac{dy}{dt}$ = $\frac{1}{2}(t-cost)^{-\frac{1}{2}}(1+sint)$
$dy$ = $\frac{1+sint}{2\sqrt {t-cost}}dt$
(b)
$\frac{dy}{dx}$ = $\frac{1}{x}cosx-\frac{1}{x^{2}}sinx$
$dy$ = $[\frac{1}{x}cosx-\frac{1}{x^{2}}sinx]dx$
