Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.8 Related Rates - 2.8 Exercises - Page 187: 33

Answer

$L$ = $5$

Work Step by Step

from the figure and given information, we have $x^{2}+y^{2}$ = $L^{2}$ $\frac{dy}{dt}$ = $-0.15$ $m/s$ $\frac{dx}{dt}$ = $0.2$ $m/s$ $x$ = $3$ $m$ differentiating implicitly with respect to $t$ we get $x^{2}+y^{2}$ = $L^{2}$ $2x\frac{dx}{dt}+2y\frac{dy}{dt}$ = $0$ $y\frac{dy}{dt}$ = $-x\frac{dx}{dt}$ $y(-0.15)$ = $-3(0.2)$ $y$ = $4$ $m$ thus $3^{2}+4^{2}$ = $L^{2}$ $L$ = $5$
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