Answer
Thus the volume is decreasing at a rate of $80$ $cm^{3}/min$
Work Step by Step
differentiating both sides of
$PV$ = $C$ with respect to $t$
$P\frac{dV}{dt}+V\frac{dP}{dt}$ = $0$
$\frac{dV}{dt}$ = $-\frac{V}{P}\frac{dP}{dt}$
$V$ = $600$, $P$ = $150$ and $\frac{dP}{dt}$ = $20$
$\frac{dV}{dt}$ = $-\frac{600}{150}(20)$ = $-80$
Thus the volume is decreasing at a rate of $80$ $cm^{3}/min$
