Answer
$v_h=60\cos(40^{\circ})\approx 45.96 \text{ ft/s}$
$v_v=60\sin(40^{\circ})\approx 38.57\text{ ft/s} $
Work Step by Step
$$v_h=v_0\cos(\theta)$$
$$v_h=60\cos(40^{\circ})\approx 45.96 \text{ ft/s}$$
$$v_v=v_0\sin(\theta)$$
$$v_v=60\sin(40^{\circ})\approx 38.57 \text{ ft/s}$$
