Answer
As a result we get $\frac{4}{7}\langle6,2,-3\rangle$.
Work Step by Step
We are given $\langle6,2,-3\rangle$. In order to get a vector with a length of $4$ we need to make the given vector into a unit vector and then scale it by a factor of $4$.
$|\langle 6,2,-3\rangle|=\sqrt{(6)^2+(2)^2+(-3)^2}=\sqrt{49}\Rightarrow\frac{1}{7}\langle6,2,-3\rangle$
Now we need to scale this vector by $4$.
$\frac{4}{7}\langle6,2,-3\rangle$
