Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.2 Vectors - 12.2 Exercises - Page 845: 13

Answer

$\lt 2,0,-2 \gt$

Work Step by Step

Find vector for $ \vec {AB}$ $ \vec {AB}=\lt x_2-x_1,y_2-y_1,z_2-z_1 \gt$ $ \vec {AB}=\lt 2-0,3-3,-1,-1 \gt$ $ \vec {AB}=\lt 2,0,-2 \gt$ The equivalent representation starting at the origin is a vector from point $(0,0)$ to the point $\lt 2,0,-2 \gt$
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