Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix C - Graphs of Second-Degree Equations - C Exercises: 4

Answer

$(x+1)^{2}+(y-5)^{2}=130$

Work Step by Step

An equation of the circle with center $(h,k)$ and radius $r$ is given as: $(x-h)^{2}+(y-k)^{2}=r^{2}$ Given: center,$(h,k)=(-1,5)$ and $(x,y)=(-4-6)$ Then $(-4+1)^{2}+(-6-5)^{2}=r^{2}$ $r^{2}=130$ Hence, $(x+1)^{2}+(y-5)^{2}=130$
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