## Calculus 8th Edition

Given: $y=x^{2}+2x$ By completing the square, we get $y+1=x^{2}+2x+1$ $y+1=(x+1)^{2}$ $y=(x+1)^{2}-1$ This is a parabola in the standard form as: $y=a(x-h)^{2}+k$ Here, $(h,k)=(-1,-1)$ which is the standard form of the equation of a parabola. The graph will be just like a graph of $y=x^{2}$ that is shifted 1 unit to the left and 1 unit downward.