Answer
$(x-3)^{2}+(y+1)^{2}=25$
Work Step by Step
An equation of the circle with center $(h,k)$ and
radius $r$ is given as:
$(x-h)^{2}+(y-k)^{2}=r^{2}$
Given: center,$(h,k)=(3,-1)$ and radius, $r=5$
Then
$(x-3)^{2}+(y+1)^{2}=5^{2}$
Hence, $(x-3)^{2}+(y+1)^{2}=25$