## Calculus 10th Edition

Published by Brooks Cole

# Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.3 Exercises: 9

#### Answer

$\frac 1 {12}(6x+sin6x)+C$

#### Work Step by Step

$\int cos^23xdx$ $\int \frac {1+cos6x} 2dx$ $\frac 1 2(x+\frac 1 6 sin6x)+C$ $\frac 1 {12}(6x+sin6x)+C$

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