Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.3 Exercises: 3

Answer

$\frac 1 {16}sin^82x+C$

Work Step by Step

$u=sin2x, du=2cos2xdx$ $\int sin^72xcos2xdx$ $\frac 1 2 \int sin^72x(2cos2x)dx$ $\frac 1 2 (\frac {sin^82x} 8)+C$ $\frac 1 {16}sin^82x+C$
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