Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.3 Exercises: 4

Answer

$-\frac {cos3x} 3 + \frac{cos^33x} 9+C$

Work Step by Step

$\int (sin3x)(sin^23x)dx$ $\int (sin3x)(1-cos^23x)dx$ $\int (sin3x-cos^23xsin3x)dx$ $\frac 1 3 \int sin3x(3)dx +\frac 1 3 \int cos^23x(-sin3x)(3)dx$ $\frac 1 3 (-cos3x)+\frac 1 3 (\frac {cos^33x} 3)+C$ $-\frac {cos3x} 3 + \frac{cos^33x} 9+C$
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