Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - 10.4 Exercises - Page 722: 36

Answer

Rectangular form equation: $x^2 + y^2 -5x = 0$ Graph:

Work Step by Step

**Remember: $cos^2(θ) + sin^2(θ) = 1$, $rcos(θ) = x$ and $rsin(θ) = y$ $r = 5cos(θ)$ $r^2 = 5rcos(θ)$ $(1)r^2 = 5rcos(θ)$ $(sin^2(θ)+cos^2(θ))r^2 =5rcos(θ)$ $r^2sin^2(θ) + r^2cos^2(θ) = 5rcos(θ)$ $y^2 + x^2 = 5x$ $x^2 + y^2 - 5x = 0$
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