Answer
$f'(x)=12x(3x^{2}+1)$
Work Step by Step
$f(x)=(3x^{2}+1)^{2}=9x^{4}+6x^{2}+1$
$f'(x)=9(4)x^{4-1}+6(2)x^{2-1}$
$f'(x)=9(4)x^{4-1}+6(2)x^{2-1}$
$f'(x)=36x^{3}+12x$
$f'(x)=12x(3x^{2}+1)$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - 2.3 Introduction To Techniques Of Differentiation - Exercises Set 2.3 - Page 140: 15
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