Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.3 Introduction To Techniques Of Differentiation - Exercises Set 2.3 - Page 140: 29

Answer

$32t$

Work Step by Step

$\frac{d}{dt}[16t^{2}]$ $=16\times2t^{2-1}$ $=32t^{1}$ $=32t$
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