Answer
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Work Step by Step
$proj_{cu}y=\frac{y\cdot (cu)}{(cu)\cdot (cu)}(cu)=\frac{c(y\cdot u)}{c^2(u\cdot u)}(cu)=\frac{c^2(y\cdot u)}{c^2(u\cdot u)}u=\frac{y\cdot u}{u\cdot u}u=proj_uy$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 6 - Orthogonality and Least Squares - 6.2 Exercises - Page 347: 31
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