Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 6 - Orthogonality and Least Squares - 6.2 Exercises - Page 347: 19

Answer

Answer: Since the vectors are orthogonal and are unit vectors, the set is orthonormal.

Work Step by Step

Note: Vectors can be rewritten using <>, so $u_{1}$ = $u_{2}$ = A set of vectors is orthonormal if the set is orthogonal and if each of the vectors is a unit vector. To determine if the set is orthonormal we must first determine if the set is orthogonal, and then we need to determine if each vector is a unit vector. 1. Determine if the set of vectors is orthogonal. Note: To determine if a set is orthogonal, each pair of vectors must be orthogonal meaning the dot product = 0. In this case, $u_{1}$∙$u_{2}$ must equal 0 to be orthogonal. $u_{1}$∙$u_{2}$ = ∙ = (-.6)(.8) + (.8)(.6) = (-.48) + .48 = 0 Since $u_{1}$∙$u_{2}$ = 0, the pair is orthogonal. Since there is only one pair, the set is orthogonal. 2. Determine if each of the vectors are unit vectors. Note: To determine if a vector is a unit vector, we take the magnitude of each vector. Unit vectors have a magnitude of 1. ||$u_{1}$|| = $\sqrt {(-.6)^{2} + (.8)^{2} }$ = $\sqrt {1}$ = 1 ||$u_{2}$|| = $\sqrt {(.8)^{2} + (.6)^{2} }$ = $\sqrt {1}$ = 1 Since the magnitudes of both $u_{1}$ and $u_{2}$ are equal to 1, both of the vectors are not unit vectors. Answer: Since the vectors are orthogonal and are unit vectors, the set is orthonormal.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.