Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 6 - Orthogonality and Least Squares - 6.2 Exercises - Page 347: 11

Answer

$proj_\vec{u}\vec{v}=\begin{bmatrix} -2\\ 1 \end{bmatrix}$

Work Step by Step

$\vec{v}=\begin{bmatrix} 1\\ 7\\ \end{bmatrix}$ and $\vec{u}=\begin{bmatrix} -4\\ 2 \end{bmatrix}$ $proj_\vec{u}\vec{v}=\frac{\vec{u}\cdot\vec{v}}{\vec{u}\cdot\vec{u}}\vec{u}=\frac{10}{20}\vec{u}=0.5\vec{u}=\begin{bmatrix} -2\\ 1 \end{bmatrix}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.