Answer
$x_1=\frac{s+1}{s+2}$ and $x_2=\frac{-s}{2(s+2)}$ where $s\ne-2$ and $s\ne0$
Work Step by Step
The system can be expressed by augmented matrix
$A=\begin{bmatrix}
s&-2\\
4s&4s
\end{bmatrix}$
$det(A)=4s^2+8s=4(s+2)$
First, replace first column with solutions
$A_1(b)=\begin{bmatrix}
1&-2\\
2&4s
\end{bmatrix}$
$det(A_1(b))=4s+4$
Next, replace second column with solutions
$A_1(b)=\begin{bmatrix}
s&1\\
4s&2
\end{bmatrix}$
$det(A_2(b))=-2s$
$x_1=\frac{4(s+1)}{4(s+2)}=\frac{s+1}{s+2}$
$x_2=\frac{-2s}{4(s+2)}=\frac{-s}{2(s+2)}$
Therefore, $s\ne-2$ and $s\ne0$
