Answer
See solution
Work Step by Step
$det(B)=ad-bc$
$det(C)=ed-cf$
$det(A)=(a+e)d-c(b+f)=ad+ed-cb-cf=det(B)+det(C)$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 3 - Determinants - 3.2 Exercises - Page 178: 41
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