Answer
See solution
Work Step by Step
$det(A)=3(-2)-(-1)6=0$
$det(B)=4(-3)-(-1)3=-9$
$det(A)det(B)=0$
$AB=\begin{bmatrix}
6&-9\\-2&3
\end{bmatrix}$
$det(AB)=6(3)-(-2)(-9)=0$
Thus, $det(AB)=det(A)det(B)$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 3 - Determinants - 3.2 Exercises - Page 178: 38
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