Answer
$-24$
Work Step by Step
$\begin{align}
\det A &=
2\begin{vmatrix}0&3\\1&5\end{vmatrix}-3\begin{vmatrix}4&3\\6&5\end{vmatrix}+(-3)\begin{vmatrix}4&0\\6&1\end{vmatrix}\\
&=2(0-3)-3(20-18)-3(4-0)\\
&=-6-6-12=-24
\end{align}$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 3 - Determinants - 3.1 Exercises - Page 169: 5
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