Answer
$1$
Work Step by Step
Expansion down across first row:
$\begin{align}
\det A & = 3\begin{vmatrix}3&2\\5&-1\end{vmatrix}-0\begin{vmatrix}2&2\\0&-1\end{vmatrix}+4\begin{vmatrix}2&3\\0&5\end{vmatrix}\\
& = 3(-3-10)-0(-2-0)+4(10-0)\\
& = -39-0+40=1
\end{align}$
Expansion down second column:
$\begin{align}
\det A & = -0\begin{vmatrix}2&2\\0&-1\end{vmatrix}+3\begin{vmatrix}3&4\\0&-1\end{vmatrix}-5\begin{vmatrix}3&4\\2&2\end{vmatrix}\\
& = -0(-2-0)+3(-3-0)-5(6-8)\\
& = -0-9+10=1
\end{align}$
