Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 3 - Determinants - 3.1 Exercises - Page 169: 2

Answer

$1$

Work Step by Step

Expansion across first row: $\begin{align} \det A & = 0\begin{vmatrix}-3&0\\3&1\end{vmatrix}-4\begin{vmatrix}5&0\\2&1\end{vmatrix}+1\begin{vmatrix}5&-3\\2&3\end{vmatrix}\\ & = 0(-3-0)-4(5-0)+1(15+6)\\ & = 0-20+21=1 \end{align}$ Expansion down second column: $\begin{align} \det A & = -4\begin{vmatrix}5&0\\2&1\end{vmatrix}-3\begin{vmatrix}0&1\\2&1\end{vmatrix}-3\begin{vmatrix}0&1\\5&0\end{vmatrix}\\ & = -4(5-0)+-3(0-2)-3(0-5)\\ & = -20+6+15=1 \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.