Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.9 Exercises - Page 80: 27

Answer

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Work Step by Step

$A=[T(e_1)\ \ T(e_2)\ \ T(e_3)]=\begin{bmatrix} 1&-5&4\\ 0&1&-6 \end{bmatrix}$~$\begin{bmatrix} 1&0&-1\\ 0&1&-1 \end{bmatrix}$ Because A has a pivot in each row, the linear transformation is onto, but because it does not have a pivot in each column, it is not one to one
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