Answer
See solution
Work Step by Step
$A=[T(e_1)\ \ T(e_2)\ \ T(e_3)\ \ T(e_4)]=\begin{bmatrix}
0&0&0&0
\\1&1&0&0
\\0&1&1&0
\\0&0&1&1
\end{bmatrix}$
The linear transformation is not one to one or onto because it does not have a pivot in each row or column.
