Answer
See solution
Work Step by Step
A must have a pivot in each column.
$A=\begin{bmatrix}
\#&*&*
\\0&\#&*
\\0&0&\#
\\0&0&0
\end{bmatrix}$ where $\#$ is a pivot and * is any scalar value.
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 1 - Linear Equations in Linear Algebra - 1.9 Exercises - Page 80: 29
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