Answer
$ \begin{bmatrix} \blacksquare&*\\ 0&0 \end{bmatrix} $ $ \begin{bmatrix} 0&\blacksquare\\ 0&0 \end{bmatrix} $ $ \begin{bmatrix} 0&0\\ 0&0 \end{bmatrix} $
Work Step by Step
The columns of a matrix are linearly dependent if and only if at least one column of does not contain a pivot position. Hence, we can have a pivot position in the first column only, in the second column only, or in neither column.
