Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 79

Answer

$4-12x^5+9x^{10}$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $ (2-3x^5)^2 ,$ is \begin{array}{l}\require{cancel} (2)^2-2(2)(3x^5)+(3x^5)^2 \\\\= 4-12x^5+9x^{10} .\end{array}
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