Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 63

Answer

$x^3-1$

Work Step by Step

Using the Distributive Property, the product of the given expression, $ (x-1)(x^2+x+1) ,$ is \begin{array}{l}\require{cancel} x(x^2)+x(x)+x(1)-1(x^2)-1(x)-1(1) \\\\= x^3+x^2+x-x^2-x-1 \\\\= x^3+(x^2-x^2)+(x-x)-1 \\\\= x^3-1 .\end{array}
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