Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 61

Answer

$x^{16}+6x^8+9$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $\left( x^8+3 \right)^2,$ is \begin{array}{l}\require{cancel} (x^8)^2+2(x^8)(3)+(3)^2 \\\\= x^{16}+6x^8+9 .\end{array}
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