## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set: 75

#### Answer

x=$\frac{4}{3}$

#### Work Step by Step

$\frac{2}{3}$x=2-$\frac{5}{6}$x 6($\frac{2}{3}$x)=6(2-$\frac{5}{6}$x) $\frac{12}{3}$x=12-$\frac{6(5)}{6}$x 4x=12-5x 4x+5x=12 9x=12 x=$\frac{12}{9}$ x=$\frac{4}{3}$

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