Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 142: 86

Answer

The equation we came up with is: $$\frac{7}{8}x - 30 = \frac{1}{2}x$$ Solving for $x$, we get: $$x = 80$$

Work Step by Step

Let us translate this statement into an algebraic equation we can solve. "$30$ is subtracted from seven-eighths of a number" means: $$\frac{7}{8}x - 30$$ The result of this expression is equal to "one-half of the number" means: $$ = \frac{1}{2}x$$ We already have both sides of the equation, so let us put them together: $$\frac{7}{8}x - 30 = \frac{1}{2}x$$ Now, we can solve for $x$ to find that unknown number: Add $30$ to both sides of the equation to get the constant on one side of the equation first: $$\frac{7}{8}x = \frac{1}{2}x + 30$$ Now, subtract $\frac{1}{2}x$ to isolate variables to the other side of the equation: $$\frac{7}{8}x - \frac{1}{2}x = 3$$ To subtract fractions, we need to find the lowest common denominator of the two fractions. In this case, the lowest common denominator is $8$, so we multiply the terms on both sides of the equation by $8$ to get rid of the fractions: $$8(\frac{7}{8}x) - 8(\frac{1}{2}x) = 8(30)$$ Divide out common factors to get rid of the fractions: $$7x - 4x = 8(30)$$ Multiply on the right-hand side to simplify: $$7x - 4x = 240$$ Combine like terms on the left-hand side of the equation: $$3x = 240$$ Divide both sides of the equation by $3$ to solve for $x$: $$x = 80$$
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