Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 37

Answer

x=1

Work Step by Step

$\frac{x}{3}$+$\frac{x}{2}$=$\frac{5}{6}$ 6($\frac{x}{3}$+$\frac{x}{2}$)=6($\frac{5}{6}$) $\frac{6x}{3}$+$\frac{6x}{2}$=5 2x+3x=5 5x=5 x=$\frac{5}{5}$ x=1 Check the answer. $\frac{1}{3}$+$\frac{1}{2}$=$\frac{5}{6}$ $\frac{1(2)}{3(2)}$+$\frac{1(3)}{2(3)}$=$\frac{5}{6}$ $\frac{2}{6}$+$\frac{3}{6}$=$\frac{5}{6}$ $\frac{5}{6}$=$\frac{5}{6}$
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